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x^2+36x-6480=0
a = 1; b = 36; c = -6480;
Δ = b2-4ac
Δ = 362-4·1·(-6480)
Δ = 27216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{27216}=\sqrt{1296*21}=\sqrt{1296}*\sqrt{21}=36\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36\sqrt{21}}{2*1}=\frac{-36-36\sqrt{21}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36\sqrt{21}}{2*1}=\frac{-36+36\sqrt{21}}{2} $
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